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223. Rectangle Area

Difficulty Topics

Description

Given the coordinates of two rectilinear rectangles in a 2D plane, return the total area covered by the two rectangles.

The first rectangle is defined by its bottom-left corner (ax1, ay1) and its top-right corner (ax2, ay2).

The second rectangle is defined by its bottom-left corner (bx1, by1) and its top-right corner (bx2, by2).

 

Example 1:

Rectangle Area

Input: ax1 = -3, ay1 = 0, ax2 = 3, ay2 = 4, bx1 = 0, by1 = -1, bx2 = 9, by2 = 2
Output: 45

Example 2:

Input: ax1 = -2, ay1 = -2, ax2 = 2, ay2 = 2, bx1 = -2, by1 = -2, bx2 = 2, by2 = 2
Output: 16

 

Constraints:

  • -104 <= ax1 <= ax2 <= 104
  • -104 <= ay1 <= ay2 <= 104
  • -104 <= bx1 <= bx2 <= 104
  • -104 <= by1 <= by2 <= 104

Solution

rectangle-area.py
class Solution:
    def computeArea(self, ax1: int, ay1: int, ax2: int, ay2: int, bx1: int, by1: int, bx2: int, by2: int) -> int:
        areaA = (ax2 - ax1) * (ay2 - ay1)
        areaB = (bx2 - bx1) * (by2 - by1)
        w = max(min(ax2, bx2) - max(ax1, bx1), 0)
        h = max(min(ay2, by2) - max(ay1, by1), 0)
        overlap = w * h

        return areaA + areaB - overlap