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446. Arithmetic Slices II - Subsequence

Difficulty Topics

Description

Given an integer array nums, return the number of all the arithmetic subsequences of nums.

A sequence of numbers is called arithmetic if it consists of at least three elements and if the difference between any two consecutive elements is the same.

  • For example, [1, 3, 5, 7, 9], [7, 7, 7, 7], and [3, -1, -5, -9] are arithmetic sequences.
  • For example, [1, 1, 2, 5, 7] is not an arithmetic sequence.

A subsequence of an array is a sequence that can be formed by removing some elements (possibly none) of the array.

  • For example, [2,5,10] is a subsequence of [1,2,1,2,4,1,5,10].

The test cases are generated so that the answer fits in 32-bit integer.

 

Example 1:

Input: nums = [2,4,6,8,10]
Output: 7
Explanation: All arithmetic subsequence slices are:
[2,4,6]
[4,6,8]
[6,8,10]
[2,4,6,8]
[4,6,8,10]
[2,4,6,8,10]
[2,6,10]

Example 2:

Input: nums = [7,7,7,7,7]
Output: 16
Explanation: Any subsequence of this array is arithmetic.

 

Constraints:

  • 1  <= nums.length <= 1000
  • -231 <= nums[i] <= 231 - 1

Solution

arithmetic-slices-ii-subsequence.py
class Solution:
    def numberOfArithmeticSlices(self, nums: List[int]) -> int:
        N = len(nums)
        dp = [defaultdict(int) for _ in range(N)]
        res = 0

        for i in range(1, N):
            for j in range(i):
                diff = nums[i] - nums[j]
                dp[i][diff] += 1

                if diff in dp[j]:
                    dp[i][diff] += dp[j][diff]
                    res += dp[j][diff]

        return res