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714. Best Time to Buy and Sell Stock with Transaction Fee

Difficulty Topics

Description

You are given an array prices where prices[i] is the price of a given stock on the ith day, and an integer fee representing a transaction fee.

Find the maximum profit you can achieve. You may complete as many transactions as you like, but you need to pay the transaction fee for each transaction.

Note: You may not engage in multiple transactions simultaneously (i.e., you must sell the stock before you buy again).

 

Example 1:

Input: prices = [1,3,2,8,4,9], fee = 2
Output: 8
Explanation: The maximum profit can be achieved by:
- Buying at prices[0] = 1
- Selling at prices[3] = 8
- Buying at prices[4] = 4
- Selling at prices[5] = 9
The total profit is ((8 - 1) - 2) + ((9 - 4) - 2) = 8.

Example 2:

Input: prices = [1,3,7,5,10,3], fee = 3
Output: 6

 

Constraints:

  • 1 <= prices.length <= 5 * 104
  • 1 <= prices[i] < 5 * 104
  • 0 <= fee < 5 * 104

Solution

best-time-to-buy-and-sell-stock-with-transaction-fee.py
class Solution:
    def maxProfit(self, prices: List[int], fee: int) -> int:
        n = len(prices)

        min_buy = prices[0]
        res = 0

        for i in range(1, n):
            if prices[i] < min_buy:
                min_buy = prices[i]

            elif prices[i] > min_buy + fee:
                res += prices[i] - min_buy - fee
                min_buy = prices[i] - fee

        return res