963. Minimum Area Rectangle II

Description

You are given an array of points in the X-Y plane points where points[i] = [xi, yi].

Return the minimum area of any rectangle formed from these points, with sides not necessarily parallel to the X and Y axes. If there is not any such rectangle, return 0.

Answers within 10-5 of the actual answer will be accepted.

 

Example 1:

Input: points = [[1,2],[2,1],[1,0],[0,1]]
Output: 2.00000
Explanation: The minimum area rectangle occurs at [1,2],[2,1],[1,0],[0,1], with an area of 2.

Example 2:

Input: points = [[0,1],[2,1],[1,1],[1,0],[2,0]]
Output: 1.00000
Explanation: The minimum area rectangle occurs at [1,0],[1,1],[2,1],[2,0], with an area of 1.

Example 3:

Input: points = [[0,3],[1,2],[3,1],[1,3],[2,1]]
Output: 0
Explanation: There is no possible rectangle to form from these points.

 

Constraints:

• 1 <= points.length <= 50
• points[i].length == 2
• 0 <= xi, yi <= 4 * 104
• All the given points are unique.

Solution

minimum-area-rectangle-ii.py

class Solution:
    def minAreaFreeRect(self, points: List[List[int]]) -> float:
        n = len(points)
        res = float('inf')
        pos = set([(x, y) for x, y in points])

        def distance(x1, y1, x2, y2):
            return (x2 - x1) ** 2 + (y2 - y1) ** 2

        for i in range(n):
            x1, y1 = points[i]
            for j in range(i + 1, n):
                x2, y2 = points[j]
                for k in range(j + 1, n):
                    x3, y3 = points[k]

                    if distance(x2, y2, x3, y3) + distance(x1, y1, x3, y3) != distance(x1, y1, x2, y2): continue

                    x4 = x1 + x2 - x3
                    y4 = y1 + y2 - y3

                    if (x4, y4) not in pos: continue

                    area = math.sqrt(distance(x1, y1, x3, y3)) * math.sqrt(distance(x2, y2, x3, y3))

                    if area == 0: continue

                    res = min(res, area)


        return res if res != float('inf') else 0