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1027. Longest Arithmetic Subsequence

Difficulty Topics

Description

Given an array nums of integers, return the length of the longest arithmetic subsequence in nums.

Recall that a subsequence of an array nums is a list nums[i1], nums[i2], ..., nums[ik] with 0 <= i1 < i2 < ... < ik <= nums.length - 1, and that a sequence seq is arithmetic if seq[i+1] - seq[i] are all the same value (for 0 <= i < seq.length - 1).

 

Example 1:

Input: nums = [3,6,9,12]
Output: 4
Explanation: 
The whole array is an arithmetic sequence with steps of length = 3.

Example 2:

Input: nums = [9,4,7,2,10]
Output: 3
Explanation: 
The longest arithmetic subsequence is [4,7,10].

Example 3:

Input: nums = [20,1,15,3,10,5,8]
Output: 4
Explanation: 
The longest arithmetic subsequence is [20,15,10,5].

 

Constraints:

  • 2 <= nums.length <= 1000
  • 0 <= nums[i] <= 500

Solution

longest-arithmetic-subsequence.py
class Solution:
    def longestArithSeqLength(self, nums: List[int]) -> int:
        dp = {}
        n = len(nums)

        for i in range(n):
            for j in range(i + 1, n):
                dp[(j, nums[j] - nums[i])] = dp.get((i, nums[j] - nums[i]), 1) + 1

        return max(dp.values())