1115. Print FooBar Alternately
Description
Suppose you are given the following code:
class FooBar { public void foo() { for (int i = 0; i < n; i++) { print("foo"); } } public void bar() { for (int i = 0; i < n; i++) { print("bar"); } } }
The same instance of FooBar
will be passed to two different threads:
- thread
A
will callfoo()
, while - thread
B
will callbar()
.
Modify the given program to output "foobar"
n
times.
Example 1:
Input: n = 1 Output: "foobar" Explanation: There are two threads being fired asynchronously. One of them calls foo(), while the other calls bar(). "foobar" is being output 1 time.
Example 2:
Input: n = 2 Output: "foobarfoobar" Explanation: "foobar" is being output 2 times.
Constraints:
1 <= n <= 1000