1200. Minimum Absolute Difference

Description

Given an array of distinct integers arr, find all pairs of elements with the minimum absolute difference of any two elements.

Return a list of pairs in ascending order(with respect to pairs), each pair [a, b] follows

a, b are from arr
a < b
b - a equals to the minimum absolute difference of any two elements in arr

Example 1:

Input: arr = [4,2,1,3]
Output: [[1,2],[2,3],[3,4]]
Explanation: The minimum absolute difference is 1. List all pairs with difference equal to 1 in ascending order.

Example 2:

Input: arr = [1,3,6,10,15]
Output: [[1,3]]

Example 3:

Input: arr = [3,8,-10,23,19,-4,-14,27]
Output: [[-14,-10],[19,23],[23,27]]

Constraints:

2 <= arr.length <= 10⁵
-10⁶ <= arr[i] <= 10⁶

Solution

minimum-absolute-difference.py

class Solution:
    def minimumAbsDifference(self, arr: List[int]) -> List[List[int]]:
        mp = collections.defaultdict(list)
        arr.sort()
        mmin = float('inf')
        n = len(arr)

        for i in range(1, n):
            diff = arr[i] - arr[i - 1]
            mmin = min(mmin, diff)
            mp[diff].append([arr[i - 1], arr[i]])

        return mp[mmin]