1296. Divide Array in Sets of K Consecutive Numbers
Description
Given an array of integers nums
and a positive integer k
, check whether it is possible to divide this array into sets of k
consecutive numbers.
Return true
if it is possible. Otherwise, return false
.
Example 1:
Input: nums = [1,2,3,3,4,4,5,6], k = 4 Output: true Explanation: Array can be divided into [1,2,3,4] and [3,4,5,6].
Example 2:
Input: nums = [3,2,1,2,3,4,3,4,5,9,10,11], k = 3 Output: true Explanation: Array can be divided into [1,2,3] , [2,3,4] , [3,4,5] and [9,10,11].
Example 3:
Input: nums = [1,2,3,4], k = 3 Output: false Explanation: Each array should be divided in subarrays of size 3.
Constraints:
1 <= k <= nums.length <= 105
1 <= nums[i] <= 109
Note: This question is the same as 846: https://leetcode.com/problems/hand-of-straights/
Solution
divide-array-in-sets-of-k-consecutive-numbers.py
class Solution:
def isPossibleDivide(self, nums: List[int], k: int) -> bool:
n = len(nums)
if n % k != 0: return False
count = collections.Counter(nums)
keys = sorted(count)
for key in keys:
if count[key] > 0:
c = count[key]
for i in range(key, key+k):
if count[i] < c: return False
count[i] -= c
return True