1300. Sum of Mutated Array Closest to Target

Description

Given an integer array arr and a target value target, return the integer value such that when we change all the integers larger than value in the given array to be equal to value, the sum of the array gets as close as possible (in absolute difference) to target.

In case of a tie, return the minimum such integer.

Notice that the answer is not neccesarilly a number from arr.

 

Example 1:

Input: arr = [4,9,3], target = 10
Output: 3
Explanation: When using 3 arr converts to [3, 3, 3] which sums 9 and that's the optimal answer.

Example 2:

Input: arr = [2,3,5], target = 10
Output: 5

Example 3:

Input: arr = [60864,25176,27249,21296,20204], target = 56803
Output: 11361

 

Constraints:

• 1 <= arr.length <= 104
• 1 <= arr[i], target <= 105

Solution

sum-of-mutated-array-closest-to-target.py

class Solution:
    def findBestValue(self, arr: List[int], target: int) -> int:

        def getSum(k):
            s = 0

            for x in arr:
                s += min(x, k)

            return s

        left, right = 0, max(arr)

        while left <= right:
            mid = left + (right - left) // 2

            total = getSum(mid)

            if total == target:
                return mid
            elif total < target:
                left = mid + 1
            else:
                right = mid - 1

        l2 = left - 1

        if abs(getSum(left) - target) < abs(getSum(l2) - target):
            return left

        return l2