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1344. Angle Between Hands of a Clock

Difficulty Topics

Description

Given two numbers, hour and minutes, return the smaller angle (in degrees) formed between the hour and the minute hand.

Answers within 10-5 of the actual value will be accepted as correct.

 

Example 1:

Input: hour = 12, minutes = 30
Output: 165

Example 2:

Input: hour = 3, minutes = 30
Output: 75

Example 3:

Input: hour = 3, minutes = 15
Output: 7.5

 

Constraints:

  • 1 <= hour <= 12
  • 0 <= minutes <= 59

Solution

angle-between-hands-of-a-clock.py
class Solution:
    def angleClock(self, hour: int, minutes: int) -> float:
        h = (hour%12) * 30 + (minutes/60 * 30)

        m = minutes/60 * 360

        angle = abs(h-m)

        if angle > 180:
            angle = 360 - angle

        return angle