1370. Increasing Decreasing String
Description
You are given a string s
. Reorder the string using the following algorithm:
- Pick the smallest character from
s
and append it to the result. - Pick the smallest character from
s
which is greater than the last appended character to the result and append it. - Repeat step 2 until you cannot pick more characters.
- Pick the largest character from
s
and append it to the result. - Pick the largest character from
s
which is smaller than the last appended character to the result and append it. - Repeat step 5 until you cannot pick more characters.
- Repeat the steps from 1 to 6 until you pick all characters from
s
.
In each step, If the smallest or the largest character appears more than once you can choose any occurrence and append it to the result.
Return the result string after sorting s
with this algorithm.
Example 1:
Input: s = "aaaabbbbcccc" Output: "abccbaabccba" Explanation: After steps 1, 2 and 3 of the first iteration, result = "abc" After steps 4, 5 and 6 of the first iteration, result = "abccba" First iteration is done. Now s = "aabbcc" and we go back to step 1 After steps 1, 2 and 3 of the second iteration, result = "abccbaabc" After steps 4, 5 and 6 of the second iteration, result = "abccbaabccba"
Example 2:
Input: s = "rat" Output: "art" Explanation: The word "rat" becomes "art" after re-ordering it with the mentioned algorithm.
Constraints:
1 <= s.length <= 500
s
consists of only lowercase English letters.
Solution
increasing-decreasing-string.py
class Solution:
def sortString(self, S: str) -> str:
mp = collections.defaultdict(int)
n = len(S)
for s in S:
mp[s] += 1
mp = dict(sorted(mp.items()))
res = []
while len(res) != n:
for key in mp:
if mp[key]:
res.append(key)
mp[key] -= 1
for key in dict(sorted(mp.items(), reverse = True)):
if mp[key]:
res.append(key)
mp[key] -= 1
return "".join(res)
increasing-decreasing-string.cpp
class Solution {
public:
string sortString(string s, string res = "") {
int cnt[26] = {};
for (auto ch : s)
++cnt[ch - 'a'];
while (res.length() != s.length()){
for (int i = 0; i < 26; i++)
res += string(--cnt[i] >= 0 ? 1 : 0, 'a' + i);
for (int i = 25; i >= 0; i--)
res += string(--cnt[i] >= 0 ? 1 : 0, 'a' + i);
}
return res;
}
};