1449. Form Largest Integer With Digits That Add up to Target
Description
Given an array of integers cost
and an integer target
, return the maximum integer you can paint under the following rules:
- The cost of painting a digit
(i + 1)
is given bycost[i]
(0-indexed). - The total cost used must be equal to
target
. - The integer does not have
0
digits.
Since the answer may be very large, return it as a string. If there is no way to paint any integer given the condition, return "0"
.
Example 1:
Input: cost = [4,3,2,5,6,7,2,5,5], target = 9 Output: "7772" Explanation: The cost to paint the digit '7' is 2, and the digit '2' is 3. Then cost("7772") = 2*3+ 3*1 = 9. You could also paint "977", but "7772" is the largest number. Digit cost 1 -> 4 2 -> 3 3 -> 2 4 -> 5 5 -> 6 6 -> 7 7 -> 2 8 -> 5 9 -> 5
Example 2:
Input: cost = [7,6,5,5,5,6,8,7,8], target = 12 Output: "85" Explanation: The cost to paint the digit '8' is 7, and the digit '5' is 5. Then cost("85") = 7 + 5 = 12.
Example 3:
Input: cost = [2,4,6,2,4,6,4,4,4], target = 5 Output: "0" Explanation: It is impossible to paint any integer with total cost equal to target.
Constraints:
cost.length == 9
1 <= cost[i], target <= 5000