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1507. Reformat Date

Difficulty Topics

Description

Given a date string in the form Day Month Year, where:

  • Day is in the set {"1st", "2nd", "3rd", "4th", ..., "30th", "31st"}.
  • Month is in the set {"Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}.
  • Year is in the range [1900, 2100].

Convert the date string to the format YYYY-MM-DD, where:

  • YYYY denotes the 4 digit year.
  • MM denotes the 2 digit month.
  • DD denotes the 2 digit day.

 

Example 1:

Input: date = "20th Oct 2052"
Output: "2052-10-20"

Example 2:

Input: date = "6th Jun 1933"
Output: "1933-06-06"

Example 3:

Input: date = "26th May 1960"
Output: "1960-05-26"

 

Constraints:

  • The given dates are guaranteed to be valid, so no error handling is necessary.

Solution

reformat-date.py
class Solution:
    def reformatDate(self, date: str) -> str:
        M = {"Jan" : "01", "Feb" : "02", "Mar" : "03", "Apr" : "04", "May" : "05", "Jun" : "06", "Jul" : "07", "Aug" : "08", "Sep" : "09", "Oct" : "10", "Nov" : "11", "Dec" : "12", }

        D = ""
        if (len(date) == 13):
            D += date[-4:] + "-" + M[date[-8:-5]] + "-" + date[:2]
        else:
            D += date[-4:] + "-" + M[date[-8:-5]] + "-0" + date[0]
        return D