1736. Latest Time by Replacing Hidden Digits
Description
You are given a string time
in the form of hh:mm
, where some of the digits in the string are hidden (represented by ?
).
The valid times are those inclusively between 00:00
and 23:59
.
Return the latest valid time you can get from time
by replacing the hidden digits.
Example 1:
Input: time = "2?:?0" Output: "23:50" Explanation: The latest hour beginning with the digit '2' is 23 and the latest minute ending with the digit '0' is 50.
Example 2:
Input: time = "0?:3?" Output: "09:39"
Example 3:
Input: time = "1?:22" Output: "19:22"
Constraints:
time
is in the formathh:mm
.- It is guaranteed that you can produce a valid time from the given string.
Solution
latest-time-by-replacing-hidden-digits.py
class Solution:
def maximumTime(self, time: str) -> str:
time = list(time)
if time[0] == "?":
if time[1] == "?" or int(time[1]) <= 3:
time[0] = "2"
else:
time[0] = "1"
if time[1] == "?":
if time[0] == "2":
time[1] = "3"
elif time[0] == "1":
time[1] = "9"
else:
time[1] = "9"
if time[3] == "?":
time[3] = "5"
if time[4] == "?":
time[4] = "9"
return "".join(time)