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1749. Maximum Absolute Sum of Any Subarray

Difficulty Topics

Description

You are given an integer array nums. The absolute sum of a subarray [numsl, numsl+1, ..., numsr-1, numsr] is abs(numsl + numsl+1 + ... + numsr-1 + numsr).

Return the maximum absolute sum of any (possibly empty) subarray of nums.

Note that abs(x) is defined as follows:

  • If x is a negative integer, then abs(x) = -x.
  • If x is a non-negative integer, then abs(x) = x.

 

Example 1:

Input: nums = [1,-3,2,3,-4]
Output: 5
Explanation: The subarray [2,3] has absolute sum = abs(2+3) = abs(5) = 5.

Example 2:

Input: nums = [2,-5,1,-4,3,-2]
Output: 8
Explanation: The subarray [-5,1,-4] has absolute sum = abs(-5+1-4) = abs(-8) = 8.

 

Constraints:

  • 1 <= nums.length <= 105
  • -104 <= nums[i] <= 104

Solution

maximum-absolute-sum-of-any-subarray.py
class Solution:
    def maxAbsoluteSum(self, nums: List[int]) -> int:
        mmax = mmin = s = 0

        for num in nums:
            s += num
            mmax = max(mmax, s)
            mmin = min(mmin, s)

        return mmax - mmin