1754. Largest Merge Of Two Strings
Description
You are given two strings word1
and word2
. You want to construct a string merge
in the following way: while either word1
or word2
are non-empty, choose one of the following options:
- If
word1
is non-empty, append the first character inword1
tomerge
and delete it fromword1
.- For example, if
word1 = "abc"
andmerge = "dv"
, then after choosing this operation,word1 = "bc"
andmerge = "dva"
.
- For example, if
- If
word2
is non-empty, append the first character inword2
tomerge
and delete it fromword2
.- For example, if
word2 = "abc"
andmerge = ""
, then after choosing this operation,word2 = "bc"
andmerge = "a"
.
- For example, if
Return the lexicographically largest merge
you can construct.
A string a
is lexicographically larger than a string b
(of the same length) if in the first position where a
and b
differ, a
has a character strictly larger than the corresponding character in b
. For example, "abcd"
is lexicographically larger than "abcc"
because the first position they differ is at the fourth character, and d
is greater than c
.
Example 1:
Input: word1 = "cabaa", word2 = "bcaaa" Output: "cbcabaaaaa" Explanation: One way to get the lexicographically largest merge is: - Take from word1: merge = "c", word1 = "abaa", word2 = "bcaaa" - Take from word2: merge = "cb", word1 = "abaa", word2 = "caaa" - Take from word2: merge = "cbc", word1 = "abaa", word2 = "aaa" - Take from word1: merge = "cbca", word1 = "baa", word2 = "aaa" - Take from word1: merge = "cbcab", word1 = "aa", word2 = "aaa" - Append the remaining 5 a's from word1 and word2 at the end of merge.
Example 2:
Input: word1 = "abcabc", word2 = "abdcaba" Output: "abdcabcabcaba"
Constraints:
1 <= word1.length, word2.length <= 3000
word1
andword2
consist only of lowercase English letters.
Solution
largest-merge-of-two-strings.py
class Solution:
def largestMerge(self, word1: str, word2: str) -> str:
res = ""
while word1 and word2:
if word1 >= word2:
res += word1[0]
word1 = word1[1:]
else:
res += word2[0]
word2 = word2[1:]
res += word1 or word2
return res
largest-merge-of-two-strings.cpp
class Solution {
public:
string largestMerge(string s, string t) {
string ans;
int i = 0, j = 0;
while(i < s.size() && j < t.size()) {
if(s.substr(i) >= t.substr(j)) {
ans += s[i];
++i;
} else {
ans += t[j];
++j;
}
}
while(i < s.size()) {
ans += s[i];
++i;
}
while(j < t.size()) {
ans += t[j];
++j;
}
return ans;
}
};