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2089. Find Target Indices After Sorting Array

Difficulty Topics

Description

You are given a 0-indexed integer array nums and a target element target.

A target index is an index i such that nums[i] == target.

Return a list of the target indices of nums after sorting nums in non-decreasing order. If there are no target indices, return an empty list. The returned list must be sorted in increasing order.

 

Example 1:

Input: nums = [1,2,5,2,3], target = 2
Output: [1,2]
Explanation: After sorting, nums is [1,2,2,3,5].
The indices where nums[i] == 2 are 1 and 2.

Example 2:

Input: nums = [1,2,5,2,3], target = 3
Output: [3]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 3 is 3.

Example 3:

Input: nums = [1,2,5,2,3], target = 5
Output: [4]
Explanation: After sorting, nums is [1,2,2,3,5].
The index where nums[i] == 5 is 4.

 

Constraints:

  • 1 <= nums.length <= 100
  • 1 <= nums[i], target <= 100

Solution

find-target-indices-after-sorting-array.py
class Solution:
    def targetIndices(self, nums: List[int], target: int) -> List[int]:
        nums.sort()
        res = []

        for i, x in enumerate(nums):
            if x == target:
                res.append(i)

        return res