2120. Execution of All Suffix Instructions Staying in a Grid
Description
There is an n x n
grid, with the top-left cell at (0, 0)
and the bottom-right cell at (n - 1, n - 1)
. You are given the integer n
and an integer array startPos
where startPos = [startrow, startcol]
indicates that a robot is initially at cell (startrow, startcol)
.
You are also given a 0-indexed string s
of length m
where s[i]
is the ith
instruction for the robot: 'L'
(move left), 'R'
(move right), 'U'
(move up), and 'D'
(move down).
The robot can begin executing from any ith
instruction in s
. It executes the instructions one by one towards the end of s
but it stops if either of these conditions is met:
- The next instruction will move the robot off the grid.
- There are no more instructions left to execute.
Return an array answer
of length m
where answer[i]
is the number of instructions the robot can execute if the robot begins executing from the ith
instruction in s
.
Example 1:
Input: n = 3, startPos = [0,1], s = "RRDDLU" Output: [1,5,4,3,1,0] Explanation: Starting from startPos and beginning execution from the ith instruction: - 0th: "RRDDLU". Only one instruction "R" can be executed before it moves off the grid. - 1st: "RDDLU". All five instructions can be executed while it stays in the grid and ends at (1, 1). - 2nd: "DDLU". All four instructions can be executed while it stays in the grid and ends at (1, 0). - 3rd: "DLU". All three instructions can be executed while it stays in the grid and ends at (0, 0). - 4th: "LU". Only one instruction "L" can be executed before it moves off the grid. - 5th: "U". If moving up, it would move off the grid.
Example 2:
Input: n = 2, startPos = [1,1], s = "LURD" Output: [4,1,0,0] Explanation: - 0th: "LURD". - 1st: "URD". - 2nd: "RD". - 3rd: "D".
Example 3:
Input: n = 1, startPos = [0,0], s = "LRUD" Output: [0,0,0,0] Explanation: No matter which instruction the robot begins execution from, it would move off the grid.
Constraints:
m == s.length
1 <= n, m <= 500
startPos.length == 2
0 <= startrow, startcol < n
s
consists of'L'
,'R'
,'U'
, and'D'
.
Solution
class Solution:
def executeInstructions(self, n: int, startPos: List[int], s: str) -> List[int]:
res = []
m = len(s)
for i in range(m):
x, y = startPos
count = 0
for j in range(i, m):
if s[j] == "R":
x, y = x, y + 1
elif s[j] == 'L':
x, y = x, y - 1
elif s[j] == 'U':
x, y = x - 1, y
else:
x, y = x + 1, y
if 0 <= x < n and 0 <= y < n:
count += 1
else:
break
res.append(count)
return res