2262. Total Appeal of A String
Description
The appeal of a string is the number of distinct characters found in the string.
- For example, the appeal of
"abbca"
is3
because it has3
distinct characters:'a'
,'b'
, and'c'
.
Given a string s
, return the total appeal of all of its substrings.
A substring is a contiguous sequence of characters within a string.
Example 1:
Input: s = "abbca" Output: 28 Explanation: The following are the substrings of "abbca": - Substrings of length 1: "a", "b", "b", "c", "a" have an appeal of 1, 1, 1, 1, and 1 respectively. The sum is 5. - Substrings of length 2: "ab", "bb", "bc", "ca" have an appeal of 2, 1, 2, and 2 respectively. The sum is 7. - Substrings of length 3: "abb", "bbc", "bca" have an appeal of 2, 2, and 3 respectively. The sum is 7. - Substrings of length 4: "abbc", "bbca" have an appeal of 3 and 3 respectively. The sum is 6. - Substrings of length 5: "abbca" has an appeal of 3. The sum is 3. The total sum is 5 + 7 + 7 + 6 + 3 = 28.
Example 2:
Input: s = "code" Output: 20 Explanation: The following are the substrings of "code": - Substrings of length 1: "c", "o", "d", "e" have an appeal of 1, 1, 1, and 1 respectively. The sum is 4. - Substrings of length 2: "co", "od", "de" have an appeal of 2, 2, and 2 respectively. The sum is 6. - Substrings of length 3: "cod", "ode" have an appeal of 3 and 3 respectively. The sum is 6. - Substrings of length 4: "code" has an appeal of 4. The sum is 4. The total sum is 4 + 6 + 6 + 4 = 20.
Constraints:
1 <= s.length <= 105
s
consists of lowercase English letters.
Solution
total-appeal-of-a-string.py
class Solution:
def appealSum(self, s: str) -> int:
n = len(s)
def go(k):
count = total = 0
for x in s:
if x == k:
total += (count * (count + 1)) // 2
count = 0
else:
count += 1
total += (count * (count + 1)) // 2
return (n * (n + 1)) // 2 - total
res = 0
for k in string.ascii_lowercase:
res += go(k)
return res