2359. Find Closest Node to Given Two Nodes
Description
You are given a directed graph of n
nodes numbered from 0
to n - 1
, where each node has at most one outgoing edge.
The graph is represented with a given 0-indexed array edges
of size n
, indicating that there is a directed edge from node i
to node edges[i]
. If there is no outgoing edge from i
, then edges[i] == -1
.
You are also given two integers node1
and node2
.
Return the index of the node that can be reached from both node1
and node2
, such that the maximum between the distance from node1
to that node, and from node2
to that node is minimized. If there are multiple answers, return the node with the smallest index, and if no possible answer exists, return -1
.
Note that edges
may contain cycles.
Example 1:
Input: edges = [2,2,3,-1], node1 = 0, node2 = 1 Output: 2 Explanation: The distance from node 0 to node 2 is 1, and the distance from node 1 to node 2 is 1. The maximum of those two distances is 1. It can be proven that we cannot get a node with a smaller maximum distance than 1, so we return node 2.
Example 2:
Input: edges = [1,2,-1], node1 = 0, node2 = 2 Output: 2 Explanation: The distance from node 0 to node 2 is 2, and the distance from node 2 to itself is 0. The maximum of those two distances is 2. It can be proven that we cannot get a node with a smaller maximum distance than 2, so we return node 2.
Constraints:
n == edges.length
2 <= n <= 105
-1 <= edges[i] < n
edges[i] != i
0 <= node1, node2 < n
Solution
find-closest-node-to-given-two-nodes.py
class Solution:
def closestMeetingNode(self, edges: List[int], node1: int, node2: int) -> int:
n = len(edges)
def gen(node):
dist = [inf] * n
visited = [False] * n
d = 0
while node != -1 and not visited[node]:
visited[node] = True
dist[node] = d
d += 1
node = edges[node]
return dist
dist1 = gen(node1)
dist2 = gen(node2)
res = inf
index = 0
for i, (a, b) in enumerate(zip(dist1, dist2)):
s = max(a, b)
if s < res:
res = s
index = i
return -1 if res == inf else index