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2404. Most Frequent Even Element

Difficulty Topics

Description

Given an integer array nums, return the most frequent even element.

If there is a tie, return the smallest one. If there is no such element, return -1.

 

Example 1:

Input: nums = [0,1,2,2,4,4,1]
Output: 2
Explanation:
The even elements are 0, 2, and 4. Of these, 2 and 4 appear the most.
We return the smallest one, which is 2.

Example 2:

Input: nums = [4,4,4,9,2,4]
Output: 4
Explanation: 4 is the even element appears the most.

Example 3:

Input: nums = [29,47,21,41,13,37,25,7]
Output: -1
Explanation: There is no even element.

 

Constraints:

  • 1 <= nums.length <= 2000
  • 0 <= nums[i] <= 105

Solution

most-frequent-even-element.py
class Solution:
    def mostFrequentEven(self, nums: List[int]) -> int:
        counter = Counter()
        have = False

        for x in nums:
            if x % 2 == 0:
                counter[x] += 1
                have = True

        if not have: return -1

        mmax = max(counter.values())

        for x in sorted(counter.keys()):
            if counter[x] == mmax:
                return x

        return -1